Compute available fault current (Isc), FLA, and recommended breaker kAIC rating — IEEE 141 & IEC 60909.
This tool estimates the symmetrical short-circuit current at the secondary terminals of a power transformer using the infinite-bus (zero source impedance) assumption. It is intended for initial selection of breaker interrupting rating (kAIC) and equipment SCCR marking per NEC 110.9 and 110.24 — not for arc-flash energy analysis or final protective coordination.
(kVA × 1000) / (√3 × V_LL)(kVA × 1000) / VFLA × (100 / %Z)Isc × 0.866Isc × 0.87√3 × V × Isc / 1000Isc × √2 × 1.85 (asymmetry factor per IEEE 141)For a 1000 kVA transformer at 480 V, 5.75 %Z, 3-phase bolted fault:
Standardized breaker interrupting ratings (kA, RMS symmetrical) per
NEMA / UL 489: 10, 14, 18, 22, 25, 35, 42, 50, 65, 100. The
calculator selects the smallest standard value ≥ Isc.
For final design, conduct a short-circuit coordination study using methods in IEEE Std 141 (Red Book) Chapter 5 or IEC 60909, with actual utility source impedance, all feeder impedances, and motor contributions. For arc-flash energy, use IEEE 1584.
Q: Is this suitable for arc-flash study?
A: No. Use IEEE 1584 methods with detailed bolted-fault MVA at each bus.
Q: Why does my %Z look "too low" (e.g., 2 %)?
A: Small impedance yields very high Isc. Confirm with the transformer
test report — for large transformers ≥ 2500 kVA, %Z is typically 5.75–8 %.
Q: Does it include DC offset?
A: Only the peak current ip. The RMS Isc shown is the symmetrical value.